作业帮(y+3)(1-3y)=1+2y^2-1/2^-2 =多少
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 07:26:46
xJ@_eV2C bQ ,.fBuQBA(؋T裔LҼg&iAtv;bahM2LQ yc.%_ |2tC
CFp|';8 bc0Nn[=
Yfvݹ.`볍_: M
(y+3)(1-3y)=1+2y^2-1/2^-2 =多少
(y+3)(1-3y)=1+2y^2
-1/2^-2 =多少
(y+3)(1-3y)=1+2y^2-1/2^-2 =多少
-1/2^-2 =-4
(y+3)(1-3y)=1+2y^2
左边=-3y^2-8y+3
所以原式为
-3y^2-8y+3=1+2y^2
移项,整理得
5y^2+8y-2=0
(y+3)(1-3y)=1+2y^2
-3y²-8y+3=1+2y²
5y²+8y-2=0
y=(-8±2√26)/10
y1=(-4+√26)/5
y2=(-4-√26)/5
-1/2^(-2)=-4
-1/2^-2 这式子有问题 至于上面的问题 -8y-3y^2+3=1+2y^2
(5y^2)+8y-2=0
y=(-4+(26)^(1/2))/5 或 y=(-4-(26)^(1/2))/5
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y (3y^2+8y-3)-6y(3y+2y-1)+9y
通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9
解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1)
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
(y-4)(3y+2)-(3y-7)(2y+1),其中y=4/3
解方程：3y²-(2y+1)(y-2)=(y-5)(y+1)
解分式方程（y+3)/(y^2+y)-1/(1-y)=4/y要过程
Y(Y-1)-(y-2)*(y+3)=2 Y的解是多少?
y-(y-1)/2=1-(2y-3)/5
2(y-1)=2y-3(y+1)
解方程3y(y-1)=2(1-y)
y-y-1/2=3-y+2/5
y^3+(x+2)e^y=1 y''(-2)
3Y-2=Y+1+6Y