解方程:(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
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解方程:(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
解方程:(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
解方程:(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
解
(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
2x²+2x-3x-3-x²+7x=x²+2x-3x-6
x²+6x-3=x²-x-6
7x=-3
x=-3/7
(2x-3)(x+1)-x(x-7)=(x-3)(x+2)
3 + 7 x == 0
x=-3/7
展开得
2x^2-3x+2x-3-(x^2-7x)=x^2-3x+2x-6
2x^2-3x+2x-3-x^2+7x=x^2-3x+2x-6
7x=-3
x=-3/7