计算.(x^2-y^2/2x^2+4xy+2y^2)*(2x+2y/x^2-xy)^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 04:58:03
x){nu4*t+mJm# OSKèVTj$铬GΆ<`55*5(u"DF@= ~
ը뉅irUqFĩZ8Ua@Rk_\g
$ qy
计算.(x^2-y^2/2x^2+4xy+2y^2)*(2x+2y/x^2-xy)^2
计算.(x^2-y^2/2x^2+4xy+2y^2)*(2x+2y/x^2-xy)^2
计算.(x^2-y^2/2x^2+4xy+2y^2)*(2x+2y/x^2-xy)^2
(x^2-y^2)/(2x^2+4xy+2y^2)*(2x+2y)/(x^2-xy)^2
=(x^2-y^2)/[2(x^2+2xy+y^2)]*2(x+y)/[x^2(x-y)^2 ]
=(x-y)(x+y)/[2(x+y)]^2*2(x+y)/[x^2(x-y)^2 ]
=(x-y)(x+y)/(x+y)*1/[x^2(x-y)^2 ]
=(x-y)/[x^2(x-y)^2 ]
=1/[x^2(x-y)]