{(x+1)/3=(y+2)/4{(x-3)/4-(y-3)/3=三分之二

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 17:51:58
{(x+1)/3=(y+2)/4{(x-3)/4-(y-3)/3=三分之二
x 0 EI8V.# Su#+>J4ʵcT*R==v't WJ9d5Jv8d~i& ՍƼ{]oA#If]>._Xwq Ç<t{o

{(x+1)/3=(y+2)/4{(x-3)/4-(y-3)/3=三分之二
{(x+1)/3=(y+2)/4{(x-3)/4-(y-3)/3=三分之二

{(x+1)/3=(y+2)/4{(x-3)/4-(y-3)/3=三分之二
(x+1)/3=(y+2)/4
(x-3)/4-(y-3)/3=2/3
4(x+1)-3(y+2)=0
3(x-3)-4(y-3)=8
4x-3y=2
3x-4y=5
16x-12y=8
9x-12y=15
16x-9x=8-15
7x=-7
x=-1
y=(4x-2)/3
y=[4*(-1)-2]/3
y=-2