计算a²/(a²-2ab)×√(a²b-4ab²+4b^3)/a+b√(a/b) (0<a<2b)
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计算a²/(a²-2ab)×√(a²b-4ab²+4b^3)/a+b√(a/b) (0<a<2b)
计算a²/(a²-2ab)×√(a²b-4ab²+4b^3)/a+b√(a/b) (0<a<2b)
计算a²/(a²-2ab)×√(a²b-4ab²+4b^3)/a+b√(a/b) (0<a<2b)
原式=a/(a-2b)×√b(a-2b)²/a+b√(a/b)
=a/(a-2b)×(2b-a)√b/a+b√a/b
=-a√b/a+b√a/b
=-√ab+√ab=0
我不是老师,不懂的请追问或HI我~
=[a/(a-2b)]×[(2b-a)√b]/[a+√(ab)]
=[-a√b]/[a+√(ab)]
=[-√(ab)]/[√a+√b]
=[b√a-a√b]/(a-b)