数学问题已知a²-3a+1=0,求a+1/a和a²+1/a²的值a²+1=3a两边除以aa+1/a=3两边平方a²+2+1/a²=9a²+1/a²=7为什么a²+2+1/a²=9
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![数学问题已知a²-3a+1=0,求a+1/a和a²+1/a²的值a²+1=3a两边除以aa+1/a=3两边平方a²+2+1/a²=9a²+1/a²=7为什么a²+2+1/a²=9](/uploads/image/z/2675525-5-5.jpg?t=%E6%95%B0%E5%AD%A6%E9%97%AE%E9%A2%98%E5%B7%B2%E7%9F%A5a%26%23178%3B-3a%2B1%3D0%2C%E6%B1%82a%2B1%2Fa%E5%92%8Ca%26%23178%3B%2B1%2Fa%26%23178%3B%E7%9A%84%E5%80%BCa%26%23178%3B%2B1%3D3a%E4%B8%A4%E8%BE%B9%E9%99%A4%E4%BB%A5aa%2B1%2Fa%3D3%E4%B8%A4%E8%BE%B9%E5%B9%B3%E6%96%B9a%26%23178%3B%2B2%2B1%2Fa%26%23178%3B%3D9a%26%23178%3B%2B1%2Fa%26%23178%3B%3D7%E4%B8%BA%E4%BB%80%E4%B9%88a%26%23178%3B%2B2%2B1%2Fa%26%23178%3B%3D9)
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数学问题已知a²-3a+1=0,求a+1/a和a²+1/a²的值a²+1=3a两边除以aa+1/a=3两边平方a²+2+1/a²=9a²+1/a²=7为什么a²+2+1/a²=9
数学问题已知a²-3a+1=0,求a+1/a和a²+1/a²的值
a²+1=3a
两边除以a
a+1/a=3
两边平方
a²+2+1/a²=9
a²+1/a²=7
为什么a²+2+1/a²=9
数学问题已知a²-3a+1=0,求a+1/a和a²+1/a²的值a²+1=3a两边除以aa+1/a=3两边平方a²+2+1/a²=9a²+1/a²=7为什么a²+2+1/a²=9
a²+2+1/a²=9是你通过计算的正确结果,不用怀疑,这还可以得
a²+1/a²=7
用这两个结果可以计算后面两个式子
a+1/a=√(a+1/a)²
=√(a²+2+1/a²)
=√9=3
a²+1/a²=7
你已经非常优秀了
能够证明a²+2+1/a²=9
(a+1/a)^2=3^2
a^2+2a*(1/a)+(1/a)^2=9
a²+2+1/a²=9