若a²-2ab+b²+2a-2b+1=0,则a-b+3=?
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若a²-2ab+b²+2a-2b+1=0,则a-b+3=?
若a²-2ab+b²+2a-2b+1=0,则a-b+3=?
若a²-2ab+b²+2a-2b+1=0,则a-b+3=?
(a-b)^2+2(a-b)+1=0
把a-b看做一个整体
(a-b+1)^2=0
a-b+1=0
a-b=-1
a-b+3=2
a²-2ab+b²+2a-2b+1=0
(a-b)²+2(a-b)+1=0
(a-b+1)²=0
a-b+1=0
a-b=-1
a-b+3=-1+3=2
a²-2ab+b²+2a-2b+1=0
(a-b)²+2(a-b)+1=0
(a-b+1)²=0
a-b+1=0
a-b=-1
所以:a-b+3=-1+3=2
原式可化简为(a-b)²+2(a-b)+1=(a-b)(a-b+2)+1=0,令a-b=x,既有x(x+2)+1=0,求出x=﹣1即a-b=﹣1,所以a-b+3=2.