如图,在梯形ABCD中,AD∥BC,∠C=90°,BE平分∠ABC且交CD于E,E为CD的中点,EF∥BC交AB于F,EG∥AB交BC这道题问解:∵EF∥BC交AB于F,EG∥AB交BC于G,∴四边形BGEF是平行四边形,∵BE平分∠ABC且交CD于E,∴∠FBE=∠EBC
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![如图,在梯形ABCD中,AD∥BC,∠C=90°,BE平分∠ABC且交CD于E,E为CD的中点,EF∥BC交AB于F,EG∥AB交BC这道题问解:∵EF∥BC交AB于F,EG∥AB交BC于G,∴四边形BGEF是平行四边形,∵BE平分∠ABC且交CD于E,∴∠FBE=∠EBC](/uploads/image/z/2684037-21-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%88%A5BC%2C%E2%88%A0C%3D90%C2%B0%2CBE%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%B8%94%E4%BA%A4CD%E4%BA%8EE%2CE%E4%B8%BACD%E7%9A%84%E4%B8%AD%E7%82%B9%2CEF%E2%88%A5BC%E4%BA%A4AB%E4%BA%8EF%2CEG%E2%88%A5AB%E4%BA%A4BC%E8%BF%99%E9%81%93%E9%A2%98%E9%97%AE%E8%A7%A3%EF%BC%9A%E2%88%B5EF%E2%88%A5BC%E4%BA%A4AB%E4%BA%8EF%2CEG%E2%88%A5AB%E4%BA%A4BC%E4%BA%8EG%2C%E2%88%B4%E5%9B%9B%E8%BE%B9%E5%BD%A2BGEF%E6%98%AF%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2%2C%E2%88%B5BE%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%B8%94%E4%BA%A4CD%E4%BA%8EE%2C%E2%88%B4%E2%88%A0FBE%3D%E2%88%A0EBC)
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