选C
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选C
选C
选C
f(x)=sin2x+acos2x=√(a²+1)sin(2x+ψ);对称轴为x=π/6
就是函数在x=π/6时取得最值;所以:f(π/6)=±√(a²+1);
即:sinπ/3+acosπ/3=±√(a²+1); 两端平方得:3a²-2√3a+1=0;
(√3a-1)²=0; a=√3/3;
所以g(x)=-(√3/3)sin2x-cos2x=-(2√3/3)[(1/2)sin2x+(√3/2)cos2x]
=(-2√3/3)sin(2x+π/3)
当:2kπ+π/2≤2x+π/3≤2kπ+3π/2;即:kπ+π/12≤x≤kπ+7π/12时,g(x)是增函数;
所以g(x)的增区间为:[kπ+π/12,kπ+7π/12]