作业帮先化简,再求值[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/17 12:35:47
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先化简,再求值[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
先化简,再求值[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
先化简,再求值[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
={a²(/a²-b²)-a²b/(a²-b²)*(a²-b²)/[ab(a+b)]}
={a²/(a²-b²)-a/[(a+b)]}
=[a²-a(a-b)]/[(a+b)(a-b)]
=b/[a+b)(a-b)]