1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
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![1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)](/uploads/image/z/2694602-2-2.jpg?t=1.%E5%B7%B2%E7%9F%A5m%5E2-5m-1%3D0%2C%E6%B1%82%28m%5E4%2B1%29%2Fm%5E2%E7%9A%84%E5%80%BC2.%E5%B7%B2%E7%9F%A5x%2F%EF%BC%88x%5E2%2Bx%2B1%29%3D1%2F4%2C%E6%B1%82x%5E2%2F%28x%5E4%2Bx%5E2%2B1%29%E7%9A%84%E5%80%BC3.%E8%8B%A5%EF%BC%884x%2B1%EF%BC%89%2F%EF%BC%88x%5E2-7x%2B10%EF%BC%89%3DA%2Fx-2%2BB%2Fx-5%2C%E6%B1%82A%E3%80%81B%E7%9A%84%E5%80%BC%EF%BC%88%E6%8F%90%E7%A4%BA%EF%BC%9A%E5%BE%85%E5%AE%9A%E7%B3%BB%E6%95%B0%E6%B3%95%EF%BC%89)
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1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
1.已知m^2-5m-1=0,求(m^4+1)/m^2的值
2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值
3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
1.已知m^2-5m-1=0,求(m^4+1)/m^2的值2.已知x/(x^2+x+1)=1/4,求x^2/(x^4+x^2+1)的值3.若(4x+1)/(x^2-7x+10)=A/x-2+B/x-5,求A、B的值(提示:待定系数法)
第三题:对右边 分母化为 x-2 x-5的乘积,化解 与左边对应,相同次数的系数相等
没带纸笔
1q
MA=-2+5M+1
MA=5M-1
=<(5M-1)4+1>/(5M-1)2
=20M-4+1/10M-2
=20M-3/IOM-2
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m*m-5m-1=0则2m*m-5m+1/m*m