当x=24/125时,代数式:(3x^3-5x^2+6x-1)-(x^3-2x^2+x-2)+(-2x^3+3x^2+1)=?
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当x=24/125时,代数式:(3x^3-5x^2+6x-1)-(x^3-2x^2+x-2)+(-2x^3+3x^2+1)=?
当x=24/125时,代数式:(3x^3-5x^2+6x-1)-(x^3-2x^2+x-2)+(-2x^3+3x^2+1)=?
当x=24/125时,代数式:(3x^3-5x^2+6x-1)-(x^3-2x^2+x-2)+(-2x^3+3x^2+1)=?
(3x^3-5x^2+6x-1)-(x^3-2x^2+x-2)+(-2x^3+3x^2+1)=?
=2x³-3x²+5x+1+(-2x^3+3x^2+1)
=0x³+0x²+5x+2
=24/25+2
=0.96+2
=2.96
根据x的幂次来化简代数式=(3x^3-x^3-2x^3)+(-5x^2+2x^2+3x^2)+(6x-x)+(-1+2+1)
=5x+2
再代入x=24/125,代数式=5*24/125+2=2又24/25
74╱25