作业帮已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷（x^2+x-6)/(x^2+3x)的值
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![已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷（x^2+x-6)/(x^2+3x)的值](/uploads/image/z/2711453-5-3.jpg?t=%E5%B7%B2%E7%9F%A5%28x-%E6%A0%B9%E5%8F%B72%2B1%29%28x-2%29%3D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%5B%28x-1%29%2F%28x-3%29-%28x-4%29%2Fx%5D%C3%B7%EF%BC%88x%5E2%2Bx-6%29%2F%28x%5E2%2B3x%29%E7%9A%84%E5%80%BC)
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已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷（x^2+x-6)/(x^2+3x)的值
已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷（x^2+x-6)/(x^2+3x)的值
已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷（x^2+x-6)/(x^2+3x)的值
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