作业帮计算:(x^2-4x+4/x^2-4-x/x+2)÷x-1/x+2.
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/16 17:58:15
x){nuӭ4*tM*M
m#+t
A,="}ِfӾOFkTikԀ9
@
`^`k Q@H%\!Vy]#(O 1 BY
计算:(x^2-4x+4/x^2-4-x/x+2)÷x-1/x+2.
计算:(x^2-4x+4/x^2-4-x/x+2)÷x-1/x+2.
计算:(x^2-4x+4/x^2-4-x/x+2)÷x-1/x+2.
原式=[(x-2)^2/(x+2)(x-2) -x/(x+2)] ×(x+2)/(x-1)
=[(x-2)/(x+2) -x/(x+2)] ×(x+2)/(x-1)
=[(-2)/(x+2)] ×(x+2)/(x-1)
=-2/(x-1)
2x*4x-3x计算
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算 x^2+4/x-2+4x/2-x
计算2x X 4x--3x=
计算(x+1)(x+2)(x+3)(x+4)
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
1.用公式计算：COSX=1-X*X/2!X*X*X*X/4!-X*X*X*X*X*X/6!.直到最后一项的绝对
计算,2/x(x+2)+2/(x+2)(x+4)+2/(x+4)(x+6)
计算:x^2-9/4-x^2*x^2+x-2/x^2-4x+3,
计算:x+2/x^2-2x-x-1/x^2-4x+4
分式计算：(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)
x+2/x²-2x-x-1/x²-4x+4计算
【计算（过程）】-x^2*(-x)^3+3x^3*(-x^2)-4(-x)*(-x)^4
计算:x^-4/(x-2)(x-1)+x^-4/(x+2)(x+1)
计算：4x(x^2-2x-1)+x(2x+5)(5-2x)