a,b,c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4=?

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a,b,c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4=?
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a,b,c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4=?
a,b,c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4=?

a,b,c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4=?
+b+c=0 ==> (a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc=0
因为a^2+b^2+c^2=0.1 所以2ab+2ac+2bc=-0.1
==>(2ab+2ac+2bc)^2=4(a^2b^2+a^2c^2+b^2c^2+2a^bc+2ab^2c+2abc^2)=0.01
因为2a^bc+2ab^2c+2abc^2=2abc(a+b+c)=0
所以a^2b^2+a^2c^2+b^2c^2=0.0025---------1
(a^2+b^2+c^2)^2=a^4+b^4+c^4+2a^2b^2+2a^2c^2+2b^2c^2=0.01---------2
由1、2式得出,a^4+b^4+c^4=0.005