x²-y²=48,x+y=6,则x=?,y=?
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x²-y²=48,x+y=6,则x=?,y=?
x²-y²=48,x+y=6,则x=?,y=?
x²-y²=48,x+y=6,则x=?,y=?
x²-y²=(x+y)(x-y)=48
x+y=6
所以x-y=8
相加
2x=14
x=7
y=6-x=-1
x²-y²=48
(x-y)(x+y)=48
x+y=6
x-y=8
2x=14
x=7
y=-1
X*2-Y*2=(X+Y)*(x-Y)=48=6*(x-Y)
x-Y=8和X+Y=6联立方程组,解得X=7,Y=-1。
x²-y²=(x+y)(x-y)=6(x-y)=48
则
x-y=8
x+y=6
解得:x=7,y=-1
x²-y²=(x+y)(x-y)=48,
x+y=6,
则x-y=8
两者相加得x=7
y=7-8=-1
不懂可以追问你,谢谢!