化简求值:(1)a²-b²/a²-ab÷(a + 2ab+b²/a),其中a=√2 - 1,b=1(2)(x-2-5/x+2)÷x-3/2x+4,其中x=√2-3.(3)1/a+1 - a+1/a²-2a+1÷a+1/a-1,其中a=√2.
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![化简求值:(1)a²-b²/a²-ab÷(a + 2ab+b²/a),其中a=√2 - 1,b=1(2)(x-2-5/x+2)÷x-3/2x+4,其中x=√2-3.(3)1/a+1 - a+1/a²-2a+1÷a+1/a-1,其中a=√2.](/uploads/image/z/2742730-34-0.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%9A%EF%BC%881%EF%BC%89a%26%23178%3B-b%26%23178%3B%2Fa%26%23178%3B-ab%C3%B7%EF%BC%88a+%2B+2ab%2Bb%26%23178%3B%2Fa%EF%BC%89%2C%E5%85%B6%E4%B8%ADa%3D%E2%88%9A2+-+1%2Cb%3D1%EF%BC%882%EF%BC%89%28x-2-5%2Fx%2B2%EF%BC%89%C3%B7x-3%2F2x%2B4%2C%E5%85%B6%E4%B8%ADx%3D%E2%88%9A2-3.%EF%BC%883%EF%BC%891%2Fa%2B1+-+a%2B1%2Fa%26%23178%3B-2a%2B1%C3%B7a%2B1%2Fa-1%2C%E5%85%B6%E4%B8%ADa%3D%E2%88%9A2.)
化简求值:(1)a²-b²/a²-ab÷(a + 2ab+b²/a),其中a=√2 - 1,b=1(2)(x-2-5/x+2)÷x-3/2x+4,其中x=√2-3.(3)1/a+1 - a+1/a²-2a+1÷a+1/a-1,其中a=√2.
化简求值:(1)a²-b²/a²-ab÷(a + 2ab+b²/a),其中a=√2 - 1,b=1
(2)(x-2-5/x+2)÷x-3/2x+4,其中x=√2-3.(3)1/a+1 - a+1/a²-2a+1÷a+1/a-1,其中a=√2.
化简求值:(1)a²-b²/a²-ab÷(a + 2ab+b²/a),其中a=√2 - 1,b=1(2)(x-2-5/x+2)÷x-3/2x+4,其中x=√2-3.(3)1/a+1 - a+1/a²-2a+1÷a+1/a-1,其中a=√2.
①原题应该是这样吧(a²-b²)/(a²-ab)÷{(a²+ 2ab+b²)}/a
如果那个a没有平方,解起来很麻烦的
如果是这样,这样化简:(a-b)(a+b)/a(a-b)÷(a+b)²/a
=(a+b)/a×a/(a+b)²
=1/(a+b)
把a=√2 - 1,b=1 代入 =1/√2
=√2 /2
②{(x-2)-5/(x+2)}÷(x-3)/(2x+4)
={(x-2)(x+2)/(x+2)-5/(x+2)}÷(x-3)/2(x+2)
=(x²-9)/(x+2)×2(x+2)/(x-3)
=(x+3)(x-3)/(x+2)×2(x+2)/(x-3)
=2(x+3)
把x=√2-3代入 =2√2
③1/(a+1) - (a+1)/(a²-2a+1)÷(a+1)/(a-1)
=1/(a+1) - (a+1)/(a-1)²×(a-1)/(a+1)
=1/(a+1) - 1/(a-1)
=(a-1)/{(a-1)(a+1)}-(a+1)/{(a-1)(a+1)}
=-2/{(a-1)(a+1)}
=-2/(a²-1)
=2/(1-a²)
把a=√2代入 =-2