2x-a/x^2+(x+3)/(x+1)=5 a为何值时方程有增根RT这才是题目...(2x-a)/(x^2-1)+(x+3)/(x+1)=5

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2x-a/x^2+(x+3)/(x+1)=5 a为何值时方程有增根RT这才是题目...(2x-a)/(x^2-1)+(x+3)/(x+1)=5
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2x-a/x^2+(x+3)/(x+1)=5 a为何值时方程有增根RT这才是题目...(2x-a)/(x^2-1)+(x+3)/(x+1)=5
2x-a/x^2+(x+3)/(x+1)=5 a为何值时方程有增根
RT
这才是题目...(2x-a)/(x^2-1)+(x+3)/(x+1)=5

2x-a/x^2+(x+3)/(x+1)=5 a为何值时方程有增根RT这才是题目...(2x-a)/(x^2-1)+(x+3)/(x+1)=5
2X-a+(X+3)(X-1)=5(X^2-1)
4X^2-2+a=0代X得
a=-2
明白了吗?

2X-a+(X+3)(X-1)=5(X^2-1)
4X^2-2+a=0代X得
a=-2

2x-a/x^2+(x+3)/(x+1)=5 a