2xy/(x^2-y2)+x/(x+y)怎么化简

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 11:50:24
2xy/(x^2-y2)+x/(x+y)怎么化简
x 0_'@bA@.'[pJ/V:YJަu+rsCBC]jXv"mxC8ɟD|I+4PtpFҴ$h+ wh]v^p4ͅD'@7cUsS5+~UvRC[nEM"朶ף 5˵#}\r.MQ9v| @O{x.

2xy/(x^2-y2)+x/(x+y)怎么化简
2xy/(x^2-y2)+x/(x+y)怎么化简

2xy/(x^2-y2)+x/(x+y)怎么化简
原式=2xy/(X^2-y^2)+x(x-y)/(x^2-y^2)
=(2xy+x^2-xy)/(x^2-y^2)
=x(x+y)/(x-y)(x+y)
=x/(x-y)

xy(xy
2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=x/x+y。分子计算后和分母约分

原式=【2xy+x(x-y)】/(x平方-y平方)=【x平方+xy]/(x平方-y平方)=x/(x-y)