设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 21:08:20
![设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)](/uploads/image/z/2758403-11-3.jpg?t=%E8%AE%BEtan2a%3D-2%E6%A0%B9%E5%8F%B72%2C%E6%B1%82cos%5Ea%2F%E6%A0%B9%E5%8F%B72-sina-1%2F2sin%28a%2B%2Fpai4%29)
xN@Eh(44,|MmGb& 4FD"3P7,
?"F
Y
_]j
)QS!kͫIF5IH?T~Y5?7u:`aCG]xOi_,gћ`A}@'
[v
/"Xiz8{*q`"XZ,=5*~Wo쏔My(q[R$Di#KkS;!Y$@-۽ECIIv
设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)
设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)
设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)
题目描述不清楚啊.
大体思路就是先把tan2a化简,得到tana的值.从而得到sina与cosa的关系式.
带入所求表达式中.
如果结果还没有出来,那就再用一次tan2a,联合sin²a+cos²a=1
算出sin²a或者cos²a的值代入