若sin(π/6-α)=1/3,则cos(2π/3十2α)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 18:24:40
若sin(π/6-α)=1/3,则cos(2π/3十2α)
x){ѽ83O|:O;f&k6mV_`gCNyg דKji%BL oEԅE jiU#Yg$YYH6 @~Ay

若sin(π/6-α)=1/3,则cos(2π/3十2α)
若sin(π/6-α)=1/3,则cos(2π/3十2α)

若sin(π/6-α)=1/3,则cos(2π/3十2α)
答:
sin(π/6-a)=1/3
sin(a-π/6)=-1/3
cos(2π/3+2a)
=cos(π-π/3+2a)
=-cos(π/3-2a)
=-cos[2(a-π/6)]
=-1+2*{sin(a-π/6) ]^2
=-1+2*(-1/3)^2
=-1+2/9
=-7/9