请问1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6).-(1/100)1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6)-(1/7)+(1/8)-(1/9)+(1/10)-(1/11)+(1/12)一直到-(1/100)我得出的结果是0.688172,#includeint main(){int sign=1;double deno=2.0,sum=1.0,term;while(deno
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/29 21:19:38
![请问1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6).-(1/100)1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6)-(1/7)+(1/8)-(1/9)+(1/10)-(1/11)+(1/12)一直到-(1/100)我得出的结果是0.688172,#includeint main(){int sign=1;double deno=2.0,sum=1.0,term;while(deno](/uploads/image/z/2761519-31-9.jpg?t=%E8%AF%B7%E9%97%AE1%2B%281%2F2%29-%281%2F3%29%2B%281%2F4%29-%281%2F5%29%2B%281%2F6%29.-%EF%BC%881%2F100%EF%BC%891%2B%281%2F2%29-%281%2F3%29%2B%281%2F4%29-%281%2F5%29%2B%281%2F6%29-%281%2F7%29%2B%281%2F8%29-%281%2F9%29%2B%281%2F10%29-%281%2F11%29%2B%281%2F12%29%E4%B8%80%E7%9B%B4%E5%88%B0-%EF%BC%881%2F100%EF%BC%89%E6%88%91%E5%BE%97%E5%87%BA%E7%9A%84%E7%BB%93%E6%9E%9C%E6%98%AF0.688172%2C%23includeint+main%28%29%7Bint+sign%3D1%3Bdouble+deno%3D2.0%2Csum%3D1.0%2Cterm%3Bwhile%28deno)
请问1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6).-(1/100)1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6)-(1/7)+(1/8)-(1/9)+(1/10)-(1/11)+(1/12)一直到-(1/100)我得出的结果是0.688172,#includeint main(){int sign=1;double deno=2.0,sum=1.0,term;while(deno
请问1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6).-(1/100)
1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6)-(1/7)+(1/8)-(1/9)+(1/10)-(1/11)+(1/12)一直到-(1/100)我得出的结果是0.688172,
#include
int main()
{
int sign=1;
double deno=2.0,sum=1.0,term;
while(deno
请问1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6).-(1/100)1+(1/2)-(1/3)+(1/4)-(1/5)+(1/6)-(1/7)+(1/8)-(1/9)+(1/10)-(1/11)+(1/12)一直到-(1/100)我得出的结果是0.688172,#includeint main(){int sign=1;double deno=2.0,sum=1.0,term;while(deno
你这个有一个小小的问题,你把int sign=1;初始话为1了,那么就是1-(1/2)+(1/3)-(1/4)+(1/5).了,应该int sign=-1就对了,结果为1.311828