作业帮f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π+θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π-θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)
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f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π+θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π-θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)
f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π+θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)
f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π-θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)
f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π+θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π-θ)-3]/[2+2cos²(π+θ)+cos(-θ)]求f(π/3)
原式=[2cos^3 θ+sin^2 θ+cosθ-3]/[2+2cos^2 θ+cosθ]
所以,f(π/3)=[2*(1/2)^3+(√3/2)^2+(1/2)-3]/[2+2*(1/2)^2+(1/2)]
=[2*(1/8)+(3/4)+(1/2)-3]/[2+2*(1/4)+(1/2)]
=(-3/2)/3
=-1/2
f(θ)=[2cos³θ+sin²(2π-θ)+cos(2π-θ)-3]/[2+2cos²(π+θ)+cos(-θ)]
=[2cos³θ+sin²(θ)+cos(θ)-3]/[2+2cos²(θ)+cos(θ)]
f(π/3) =[2(1/2)³+3/4+1/2-3]/[2+2(1/2)²+1/2]
=(-3/2)/(3)
=-1/2