若函数f(x)=(x-1)(x-2)(x-3)...(x-2013) 则f′(2013)=____

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若函数f(x)=(x-1)(x-2)(x-3)...(x-2013) 则f′(2013)=____
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若函数f(x)=(x-1)(x-2)(x-3)...(x-2013) 则f′(2013)=____
若函数f(x)=(x-1)(x-2)(x-3)...(x-2013) 则f′(2013)=____

若函数f(x)=(x-1)(x-2)(x-3)...(x-2013) 则f′(2013)=____
记g(x)=(x-1)(x-2)..(x-2012)
则f(x)=g(x)(x-2013)
f'(x)=g'(x)(x-2013)+g(x)
f'(2013)=g(2013)=2012*2011*...*2*1=2012!