解一元二次方程,(1)(x+1)²-3=0 (2) 4(x+2)²=x+2
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解一元二次方程,(1)(x+1)²-3=0 (2) 4(x+2)²=x+2
解一元二次方程,
(1)(x+1)²-3=0 (2) 4(x+2)²=x+2
解一元二次方程,(1)(x+1)²-3=0 (2) 4(x+2)²=x+2
(1)(x+1)²-3=0
(x+1)²=3
x+1=±根号3,
x=±根号3-1
x1=根号3-1,x2=-根号3-1
(2) 4(x+2)²=x+2
4(x+2)²-(x+2)=0
(x+2)(4x+8-1)=0
(x+2)(4x+7)=0
x1=-2,x2=-7/4
1)(x+1)²-3=0
x+1=±根号3
x=根号3-1或x=-根号3-1
(2) 4(x+2)²=x+2
x+2=0时,x=-2
x+2≠0时,4(x+2)=1
x+2=1/4
x=-7/4