a²+b²+c²=1,则ab+bc+ca的最大值我是这么做的∵(a-b-c)^2>=0所以a^2+b^2+c^2-2ab-2bc-2ac>=0a^2+b^2+c^2>=2ab+2bc+2ac所以最大值为0.5这个错在哪里了.
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![a²+b²+c²=1,则ab+bc+ca的最大值我是这么做的∵(a-b-c)^2>=0所以a^2+b^2+c^2-2ab-2bc-2ac>=0a^2+b^2+c^2>=2ab+2bc+2ac所以最大值为0.5这个错在哪里了.](/uploads/image/z/2805727-31-7.jpg?t=a%26%23178%3B%EF%BC%8Bb%26%23178%3B%EF%BC%8Bc%26%23178%3B%EF%BC%9D1%2C%E5%88%99ab%2Bbc%2Bca%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%88%91%E6%98%AF%E8%BF%99%E4%B9%88%E5%81%9A%E7%9A%84%E2%88%B5%28a-b-c%29%5E2%3E%3D0%E6%89%80%E4%BB%A5a%5E2%2Bb%5E2%2Bc%5E2-2ab-2bc-2ac%3E%3D0a%5E2%2Bb%5E2%2Bc%5E2%3E%3D2ab%2B2bc%2B2ac%E6%89%80%E4%BB%A5%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA0.5%E8%BF%99%E4%B8%AA%E9%94%99%E5%9C%A8%E5%93%AA%E9%87%8C%E4%BA%86.)
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