ab(c²-d²)-(a²-b²)cd如何因式分解?
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![ab(c²-d²)-(a²-b²)cd如何因式分解?](/uploads/image/z/2805802-34-2.jpg?t=ab%EF%BC%88c%26%23178%3B-d%26%23178%3B%EF%BC%89-%EF%BC%88a%26%23178%3B-b%26%23178%3B%EF%BC%89cd%E5%A6%82%E4%BD%95%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%3F)
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ab(c²-d²)-(a²-b²)cd如何因式分解?
ab(c²-d²)-(a²-b²)cd如何因式分解?
ab(c²-d²)-(a²-b²)cd如何因式分解?
ab(c²-d²)-(a²-b²)cd
=abc²-abd²-a²cd+b²cd
=bc(ac+bd)-ad(bd+ac)
=(ac+bd)(bc-ad)
原式=abc²-abd²-a²cd+b²cd
=(abc²-a²cd)+(b²cd-abd²)
=ac(bc-ad)+bd(bc-ad)
=(bc-ad)(ac+bd)
原式=abc2-abd2-a2cd+b2cd=ac(bc-ad)-bd(ad-bc)=-(ac-bd)(bc-ad)