1.若|a+1|+|b-3|+|c|=0,求(a-b)^2-(b-c)^2-(c-a)^2和值.(注:^2表示二次幂)2.已知a,b互为相反数,c,d互为倒数,x的绝对值为5,求:x^2-(a+b+cd)x+(a+b)^19983.(0.125)^1995×[(-2)^1995]^3
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![1.若|a+1|+|b-3|+|c|=0,求(a-b)^2-(b-c)^2-(c-a)^2和值.(注:^2表示二次幂)2.已知a,b互为相反数,c,d互为倒数,x的绝对值为5,求:x^2-(a+b+cd)x+(a+b)^19983.(0.125)^1995×[(-2)^1995]^3](/uploads/image/z/2830480-16-0.jpg?t=1.%E8%8B%A5%7Ca%2B1%7C%2B%7Cb-3%7C%2B%7Cc%7C%3D0%2C%E6%B1%82%EF%BC%88a-b%29%5E2-%28b-c%29%5E2-%28c-a%29%5E2%E5%92%8C%E5%80%BC.%EF%BC%88%E6%B3%A8%EF%BC%9A%5E2%E8%A1%A8%E7%A4%BA%E4%BA%8C%E6%AC%A1%E5%B9%82%EF%BC%892.%E5%B7%B2%E7%9F%A5a%2Cb%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2Cc%2Cd%E4%BA%92%E4%B8%BA%E5%80%92%E6%95%B0%2Cx%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%B8%BA5%2C%E6%B1%82%EF%BC%9Ax%5E2-%28a%2Bb%2Bcd%29x%2B%28a%2Bb%29%5E19983.%EF%BC%880.125%29%5E1995%C3%97%5B%28-2%29%5E1995%5D%5E3)
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