现已从答案知道下列说法全部错误,但我不知道错在哪,若x1,x2属于A,当x1<x2时,f(x1)<f(x2),则y=f(x)在A上是增函数;函数y=-1\x在定义域上是增函数;y=1\x的单调区间是(-无穷,0)U(0,+无
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![现已从答案知道下列说法全部错误,但我不知道错在哪,若x1,x2属于A,当x1<x2时,f(x1)<f(x2),则y=f(x)在A上是增函数;函数y=-1\x在定义域上是增函数;y=1\x的单调区间是(-无穷,0)U(0,+无](/uploads/image/z/2835741-21-1.jpg?t=%E7%8E%B0%E5%B7%B2%E4%BB%8E%E7%AD%94%E6%A1%88%E7%9F%A5%E9%81%93%E4%B8%8B%E5%88%97%E8%AF%B4%E6%B3%95%E5%85%A8%E9%83%A8%E9%94%99%E8%AF%AF%2C%E4%BD%86%E6%88%91%E4%B8%8D%E7%9F%A5%E9%81%93%E9%94%99%E5%9C%A8%E5%93%AA%2C%E8%8B%A5x1%2Cx2%E5%B1%9E%E4%BA%8EA%2C%E5%BD%93x1%EF%BC%9Cx2%E6%97%B6%2Cf%EF%BC%88x1%EF%BC%89%EF%BC%9Cf%EF%BC%88x2%EF%BC%89%2C%E5%88%99y%3Df%EF%BC%88x%EF%BC%89%E5%9C%A8A%E4%B8%8A%E6%98%AF%E5%A2%9E%E5%87%BD%E6%95%B0%EF%BC%9B%E5%87%BD%E6%95%B0y%3D-1%5Cx%E5%9C%A8%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%8A%E6%98%AF%E5%A2%9E%E5%87%BD%E6%95%B0%EF%BC%9By%3D1%5Cx%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4%E6%98%AF%EF%BC%88-%E6%97%A0%E7%A9%B7%2C0%EF%BC%89U%EF%BC%880%2C%2B%E6%97%A0)
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