已知 H2(g)+Cl2(g)=2HCl(g)△H=-890KJ/mol 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )A.+184.6KJ/mol B.-92.3KJ/mol C.-369.2KJ/mol D.+92.3KJ/mol
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![已知 H2(g)+Cl2(g)=2HCl(g)△H=-890KJ/mol 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )A.+184.6KJ/mol B.-92.3KJ/mol C.-369.2KJ/mol D.+92.3KJ/mol](/uploads/image/z/2876265-9-5.jpg?t=%E5%B7%B2%E7%9F%A5+H2%EF%BC%88g%29%2BCl2%28g%29%3D2HCl%28g%29%E2%96%B3H%3D-890KJ%EF%BC%8Fmol+%E5%88%99%E5%8F%8D%E5%BA%94HCl%28g%29%3D1%EF%BC%8F2H2%28g%29%2B1%EF%BC%8F2Cl2%28g%29%E7%9A%84%E2%96%B3H%E4%B8%BA%EF%BC%88+%EF%BC%89A.%2B184.6KJ%EF%BC%8Fmol+B.-92.3KJ%EF%BC%8Fmol+C.-369.2KJ%EF%BC%8Fmol+D.%2B92.3KJ%EF%BC%8Fmol)
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已知 H2(g)+Cl2(g)=2HCl(g)△H=-890KJ/mol 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )A.+184.6KJ/mol B.-92.3KJ/mol C.-369.2KJ/mol D.+92.3KJ/mol
已知 H2(g)+Cl2(g)=2HCl(g)
△H=-890KJ/mol
则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )
A.+184.6KJ/mol B.-92.3KJ/mol
C.-369.2KJ/mol D.+92.3KJ/mol
已知 H2(g)+Cl2(g)=2HCl(g)△H=-890KJ/mol 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )A.+184.6KJ/mol B.-92.3KJ/mol C.-369.2KJ/mol D.+92.3KJ/mol
这个题有错误吧,答案应该是+445啊