"(x+1)^2-4(x+1)+4" x-1=3的算木平方根

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/02 15:28:30
x)SҨ6Ԍ353M*t mjyn9+lg v$铢\Άd+*4*tM*5.\Ȩh-~OkhdhTT5$:&!ԁd Lr 3tM+aON5ҩ5|m:O?okrx:P.Ȁ8#05Jյ/.H̳bQp

"(x+1)^2-4(x+1)+4" x-1=3的算木平方根
"(x+1)^2-4(x+1)+4" x-1=3的算木平方根

"(x+1)^2-4(x+1)+4" x-1=3的算木平方根
x^2y^2(x-4y)(x+4y)-x^2y^2(x-2y)^2 =x^2y^2(x^2-16y^2-x^2+4xy-4y^2)
=x^2y^2(4xy-20y^2)
=4x^2y^3(x-5y)
当x=-2,y=1/2时,原式=4×(-2)^2×(1/2)^3×(-2-5×1/2)=-9

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5-x^4+x^3-x^2+x-1 x^6-x^5+x^4-x^2+x-1 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6 如下9*9宫图如何填x x x 1 x x x 2 9x x 5 x x x x x 4x 6 8 x x x x x xx x x 7 x x 5 x xx 2 x x 6 x x 8 xx x 3 x x 9 x x xx x x x 5 x 1 6 x 4 x x x 3 x x x x 7 x x x x 2 x x x 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 化简:[(x+2)/x-(x-1)/(x-2)]/[(x-4)/(x^2-4x+4)] 【{x²-4x+4/x²-4}-x/x+2】÷x-1/x+2 [x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简 lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷 计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3) a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3 (x/x-2)+(2/x*2+2x)-(x+6/x*2-4)化简,=x^2/x(x-2)+(2x-4)/x(x^2-4)-(x^2+6x)/x(x^2-4)=x^2/x(x-2)-(x+2)/x(x-2)=(x-2)(x+1)/x(x-2)=(x+1)/x (x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x)