因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/14 10:45:55
因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)
x){:{=O;^,_lTgamdYgahkYmkh~OGl{:laPDèBPS#QHSP8Q&H [_`gC{o7F$ V_-P\ b!D H. m8M@'D#]3b] $wQQA =<;PX⾵

因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)
因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)
答案为(2x-1)(x^2+(a+12)+11-3a)

因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11(a为常数)答案为(2x-1)(x^2+(a+12)+11-3a)
2x^3+(2a+23)x^2+(10-7a)x+3a-11
=2x^3-x^2+x^2+(2a+23)x^2+(10-7a)x+3a-11
=x^2*(2x-1)+(2a+24)x^2-(a+12)x+(a+12)x+(10-7a)x+3a-11
=x^2*(2x-1)+(a+12)x(2x-1)+(22-6a)x-(11-3a)
=x^2*(2x-1)+(a+12)x(2x-1)+(11-3a)(2x-1)
=(2x-1)(x^2+(a+12)+11-3a).