已知根号a-1+(ab-2)²=0,求a 4b的平方根 (求正确的答案!)
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已知根号a-1+(ab-2)²=0,求a 4b的平方根 (求正确的答案!)
已知根号a-1+(ab-2)²=0,求a 4b的平方根 (求正确的答案!)
已知根号a-1+(ab-2)²=0,求a 4b的平方根 (求正确的答案!)
根号a-1+(ab-2)²=0
所以a-1=ab-2=0
a=1
b=2/a=2
所以a+4b=9
所以a+4b的平方根是-3和3
∵根号a-1≥0,(ab-2)²≥0,
且根号a-1+(ab-2)²=0,
∴根号a-1=0,(ab-2)²=0,
∴a=1,b=2
∴±根号(a×4b)
=±根号(1×2×4)
=±根号8
=±2倍根号2