设a>0,函数f(x)=ax+1-x/a,x属于【0,1】,(1)当a=2时,求f(x)的最大值;(2)记f(x)的最大值g(x),求g(X)的表达式f(x)=ax+ 1-x/a,
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![设a>0,函数f(x)=ax+1-x/a,x属于【0,1】,(1)当a=2时,求f(x)的最大值;(2)记f(x)的最大值g(x),求g(X)的表达式f(x)=ax+ 1-x/a,](/uploads/image/z/2985259-67-9.jpg?t=%E8%AE%BEa%3E0%2C%E5%87%BD%E6%95%B0f%28x%29%3Dax%2B1-x%2Fa%2Cx%E5%B1%9E%E4%BA%8E%E3%80%900%2C1%E3%80%91%2C%281%29%E5%BD%93a%3D2%E6%97%B6%2C%E6%B1%82f%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%3B%282%29%E8%AE%B0f%28x%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BCg%28x%29%2C%E6%B1%82g%28X%29%E7%9A%84%E8%A1%A8%E8%BE%BE%E5%BC%8Ff%28x%29%3Dax%2B+1-x%2Fa%2C)
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