已知集合A={x|2x²-ax+b=0},B={x|6x²+(a+2)x+b=0},若A∩B={1},求A∪B
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 15:11:53
![已知集合A={x|2x²-ax+b=0},B={x|6x²+(a+2)x+b=0},若A∩B={1},求A∪B](/uploads/image/z/3000286-46-6.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%7Bx%7C2x%26%23178%3B-ax%2Bb%3D0%7D%2CB%3D%7Bx%7C6x%26%23178%3B%2B%28a%2B2%29x%2Bb%3D0%7D%2C%E8%8B%A5A%E2%88%A9B%3D%7B1%7D%2C%E6%B1%82A%E2%88%AAB)
x){}K_n{:ѶƨBMZ7B;֠V $jH6҄ʼ^c%PaγM@*'"}_`gC+>2|{VɏjycɓM|EkAhkdkiGӎ@E:@e@(8Af@;^
"c_\g( mO
已知集合A={x|2x²-ax+b=0},B={x|6x²+(a+2)x+b=0},若A∩B={1},求A∪B
已知集合A={x|2x²-ax+b=0},B={x|6x²+(a+2)x+b=0},若A∩B={1},求A∪B
已知集合A={x|2x²-ax+b=0},B={x|6x²+(a+2)x+b=0},若A∩B={1},求A∪B
把1代入集合A、B的两个方程中,求得a=-3,b=-5,再分别代入方程求x,得A={1,-5/2}, B={1,-5/6},所以A∪B={1,-5/2,-5/6}