x^2+2xy-3y^2+3x+y+2因式分解

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x^2+2xy-3y^2+3x+y+2因式分解
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x^2+2xy-3y^2+3x+y+2因式分解
x^2+2xy-3y^2+3x+y+2
因式分解

x^2+2xy-3y^2+3x+y+2因式分解
你一定是一个初中生吧,那你应该知道十字相乘法
x^2+2xy-3y^2+3x+y+2
=(x^2+2xy-3y^2)+x+3y+2x-2y+2
=(x+3y)(x-y)+(x+3y)+2(x-y+1)
=(x+3y)(x-y+1)+2(x-y+1)
=(x+3y+2)(x-y+1)

支持一楼楼主!!!

(x+3y+2)(x-y+1)
此类题目可以用待定系数法求解.
过程如下:
设(x+ay+b)(x+cy+d)
由已知得:a+c=2
ac=-3
bd=2
b+d=3
解得a=3,b=2,c=-1,d=1
即上述答案.

因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y) X^Y-2XY^2+y^3 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) 化简：x-y/x+3y÷x^-y^2/x^2+6xy+9y^2-(xy/x+y) [x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y [x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y [x(x^2y^2-xy)-y(x^2-x^3y)]/(2x^2y) 因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6 -xy^2(x+y)^3+x(x+y)^2因式分解 (x+3y)/(x^2+xy)-x+y计算题 x*x+xy=3,xy+y*y=2,则x*x+2xy+y*y=________? (x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)答案应为-2x-x*x-3x， x^2-xy-6y^2+3xy+y+2 (x+y)(x-y)-(2xy+3y)平方平方是(2xy+3y)的 化简：3x^2-[5xy-(x^y-3xy)+4x^2y-8xy] 3y/x*x-y*y+x/x*x-2xy+y*y+6y*y/x*x*x-x*x*y-xy*y+y*y*y等于多少? (-x+2y)(2x+y)-(2x+y)(y-2x)-3xy=?因式分解 (3xy)^2÷(-xy)+(x-2y)^2-(x+2y)(x-2y)