3[x-2(x-1)]=9x怎么做
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 18:59:38
x)35Ҩ5ԌxdgY6IE8l|cɋ};_\dRcLq_mWyF` o72
lsP1Md&k\mm1j" ]
3[x-2(x-1)]=9x怎么做
3[x-2(x-1)]=9x怎么做
3[x-2(x-1)]=9x怎么做
两边除以3
x-2(x-1)=3x
x-2x+2=3x
3x-x+2x=2
4x=2
x=2÷4
x=1/2
3[x-2(x-1)]=9x
3(-x+2)=9x
-3x+6=9x
12x=6
x=1/2
3[x-2(x-1)]=9x怎么做
x-1/x-2-x-3/x-4=x-2/x-3-x-4/x-5怎么做?
(x-1)(x+2)(x+3)(x+6)怎么做?
(2x+3)(-x-1)怎么做
(2x+3)(-x-1)怎么做
2(x-3)(-x+1)怎么做
3分之x-1=5分之x+2+x 怎么做? 怎么做?
2(x-2)-3(4x-1)=9(1-x)怎么做过程
(3x+2)(X+3)=x+14怎么做
x/x-1+2=5/x-1怎么做?
X(X-4)=3X+1怎么做
x+2x/3+x-80=720怎么做
4x-14=(x+2)*(x-3)怎么做
(x-1)(x-2)(x+3)怎么做
(X-1)(x-2)(x-3)怎么做呀?
[3-2x/1-x]-1=[x+2/x-3]怎么做
1/(x+2)+1/(x+3)=1/(x+1)+1/(x+4)怎么做
数学分式方程3/(x-1)(x+2)=x-1/x-1怎么做?