A=a²+b²-c ² B=-4a²+2b²+3c²,且A+B+C=0,求多项式C若a=1,b=-1.c=3,A+B=?
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![A=a²+b²-c ² B=-4a²+2b²+3c²,且A+B+C=0,求多项式C若a=1,b=-1.c=3,A+B=?](/uploads/image/z/3002620-4-0.jpg?t=A%3Da%26%23178%3B%2Bb%26%23178%3B-c+%26%23178%3B+B%3D-4a%26%23178%3B%2B2b%26%23178%3B%2B3c%26%23178%3B%2C%E4%B8%94A%2BB%2BC%3D0%2C%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8FC%E8%8B%A5a%3D1%EF%BC%8Cb%3D-1.c%3D3%2CA%2BB%3D%3F)
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A=a²+b²-c ² B=-4a²+2b²+3c²,且A+B+C=0,求多项式C若a=1,b=-1.c=3,A+B=?
A=a²+b²-c ² B=-4a²+2b²+3c²,且A+B+C=0,求多项式C
若a=1,b=-1.c=3,A+B=?
A=a²+b²-c ² B=-4a²+2b²+3c²,且A+B+C=0,求多项式C若a=1,b=-1.c=3,A+B=?
A+B+C=0,C=-(A+B)=-(a^2+b^2-c^2-4a^2++2b²+3c²)=3a²-3b²-2c ²
A+B=-C=-3a²+3b²+2c ²=-3+3+18=18
把A和B带入后边的那个式子,在计算,应该可以算出来的