用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
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用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
用因式分解法解下列因式:
① 9(x+2)²=16(2x-5)²
②(x+3)²-5(x+3)+6=0
用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
① 9(x+2)²=16(2x-5)²
9(x+2)²-16(2x-5)²=0
[3(x+2)+4(2x-5)][3(x+2)-4(2x-5)]=0
∴3(x+2)+4(2x-5)=0或3(x+2)-4(2x-5)=0
解得:x1=14/11,x2=26/5
②(x+3)²-5(x+3)+6=0
[(x+3)-2][(x+3)-3]=0
(x+3)-2=0或(x+3)-3=0
∴x1=-1,x2=0
3(x+2)= 4(2x-5) 3(x+2)= - 4( 2x-...
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3(x+2)= 4(2x-5) 3(x+2)= - 4( 2x-5) 3x+6=8x-20 3X+6=-8X+20 5X=26 11X=14 X=26/5 X=14/11 【 (x+3)-2] [ (x+3) -3 ] =0 (x+1) *x=0 x+1=0 x=0 x=-1 Or x=0
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