用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0

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用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
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用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
用因式分解法解下列因式:
① 9(x+2)²=16(2x-5)²
②(x+3)²-5(x+3)+6=0

用因式分解法解下列因式:① 9(x+2)²=16(2x-5)²②(x+3)²-5(x+3)+6=0
① 9(x+2)²=16(2x-5)²
9(x+2)²-16(2x-5)²=0
[3(x+2)+4(2x-5)][3(x+2)-4(2x-5)]=0
∴3(x+2)+4(2x-5)=0或3(x+2)-4(2x-5)=0
解得:x1=14/11,x2=26/5
②(x+3)²-5(x+3)+6=0
[(x+3)-2][(x+3)-3]=0
(x+3)-2=0或(x+3)-3=0
∴x1=-1,x2=0

  1.       3(x+2)=   4(2x-5)                  3(x+2)= -  4(  2x-...

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    1.       3(x+2)=   4(2x-5)                  3(x+2)= -  4(  2x-5)

                 3x+6=8x-20                          3X+6=-8X+20

                       5X=26                                 11X=14

                          X=26/5                                  X=14/11

    2.    【  (x+3)-2]   [    (x+3)  -3  ]  =0

                  (x+1)  *x=0

                x+1=0         x=0

                 x=-1       Or    x=0

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