2x-y-z=3 4x+2y-z=15 4x+3y=18
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2x-y-z=3 4x+2y-z=15 4x+3y=18
2x-y-z=3 4x+2y-z=15 4x+3y=18
2x-y-z=3 4x+2y-z=15 4x+3y=18
设2x-y-z=3为(1)式,依次设为(2)式,(3)式.
将(1)-(2)式=-2x-3y=-12.即为2x+3y=12,
再用(3)式减去2x+3y=12,可以得到2x=6,所以x=3.
接下去把x=3代入(3)式解出y=2,再把x=3,y=2代入(1)式,得到z=1
就是利用消元的方法.
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
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