(x+1)/(x²-1)-(1/3x)=1/(3x-3)(x²-1),-1的话分母为0
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(x+1)/(x²-1)-(1/3x)=1/(3x-3)(x²-1),-1的话分母为0
(x+1)/(x²-1)-(1/3x)=1/(3x-3)
(x²-1),-1的话分母为0
(x+1)/(x²-1)-(1/3x)=1/(3x-3)(x²-1),-1的话分母为0
(x²-1)平方差公式=(x+1)*(x-1)
除以一个数等于乘以它的倒数
打起来太麻烦了,思路跟你讲了.自己努力下.化简掉~上面提示你的.
(x+1)/(x+1)(x-1)-1/3x=1/3(x-1)
2/3(x-1)=1/3x
2/x-1=1/x
x=-1