作业帮定义两种运算：a⊕b=√(a²-b²),a⊙b=√(a-b)²1﹚求f(x)=﹙2⊕x﹚/[﹙x⊕2﹚-2]的解析式和定义域2﹚判断f﹙x﹚=﹙2⊕x﹚/[﹙x⊕2﹚-2]的奇偶性
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![定义两种运算：a⊕b=√(a²-b²),a⊙b=√(a-b)²1﹚求f(x)=﹙2⊕x﹚/[﹙x⊕2﹚-2]的解析式和定义域2﹚判断f﹙x﹚=﹙2⊕x﹚/[﹙x⊕2﹚-2]的奇偶性](/uploads/image/z/3008960-8-0.jpg?t=%E5%AE%9A%E4%B9%89%E4%B8%A4%E7%A7%8D%E8%BF%90%E7%AE%97%EF%BC%9Aa%E2%8A%95b%3D%E2%88%9A%28a%26%23178%3B-b%26%23178%3B%29%2Ca%E2%8A%99b%3D%E2%88%9A%28a-b%29%26%23178%3B1%EF%B9%9A%E6%B1%82f%28x%29%3D%EF%B9%992%E2%8A%95x%EF%B9%9A%2F%5B%EF%B9%99x%E2%8A%952%EF%B9%9A-2%5D%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%92%8C%E5%AE%9A%E4%B9%89%E5%9F%9F2%EF%B9%9A%E5%88%A4%E6%96%ADf%EF%B9%99x%EF%B9%9A%3D%EF%B9%992%E2%8A%95x%EF%B9%9A%2F%5B%EF%B9%99x%E2%8A%952%EF%B9%9A-2%5D%E7%9A%84%E5%A5%87%E5%81%B6%E6%80%A7)
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定义两种运算：a⊕b=√(a²-b²),a⊙b=√(a-b)²1﹚求f(x)=﹙2⊕x﹚/[﹙x⊕2﹚-2]的解析式和定义域2﹚判断f﹙x﹚=﹙2⊕x﹚/[﹙x⊕2﹚-2]的奇偶性
定义两种运算：a⊕b=√(a²-b²),a⊙b=√(a-b)²
1﹚求f(x)=﹙2⊕x﹚/[﹙x⊕2﹚-2]的解析式和定义域
2﹚判断f﹙x﹚=﹙2⊕x﹚/[﹙x⊕2﹚-2]的奇偶性
定义两种运算：a⊕b=√(a²-b²),a⊙b=√(a-b)²1﹚求f(x)=﹙2⊕x﹚/[﹙x⊕2﹚-2]的解析式和定义域2﹚判断f﹙x﹚=﹙2⊕x﹚/[﹙x⊕2﹚-2]的奇偶性
1 定义域为{x/x>0且x不等于2} f[x]=根号下2的平方-x2/[根号下[x-2]]-2
2奇函数 .
阿孔答,小米,这题你仔细想想其实很简单
不懂
只需要依葫芦现瓢即可