如果实数x,y满足不等式组x≥1,x-y+1≤0,2x-y-2≤0,则x²+y²的最小值是
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如果实数x,y满足不等式组x≥1,x-y+1≤0,2x-y-2≤0,则x²+y²的最小值是
如果实数x,y满足不等式组x≥1,x-y+1≤0,2x-y-2≤0,则x²+y²的最小值是
如果实数x,y满足不等式组x≥1,x-y+1≤0,2x-y-2≤0,则x²+y²的最小值是
x≥1.(1)
x-y+1≤0.(2)
2x-y-2≤0.(3)
由(2),y≥x+1,而x≥1,∴y≥2
由(3),y≥2(x-1),y≥0
综上:x≥1,y≥2
x²+y²≥1^2+2^2=5
最小值5
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