﹙x²-x﹚²-18﹙x²-x﹚+72
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﹙x²-x﹚²-18﹙x²-x﹚+72
﹙x²-x﹚²-18﹙x²-x﹚+72
﹙x²-x﹚²-18﹙x²-x﹚+72
=[(x²-x)-12]×[(x²-x)-6]
=(x²-x-12)(x²-x-6)
=(x-4)(x+3)(x-3)(x+2)
﹙x²-x﹚²-18﹙x²-x﹚+72
=(x²-x-6)(x²-x-12)
=(x-3)(x+2)(x-4)(x+3)
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﹙x²-x﹚²-18﹙x²-x﹚+72
=(x²-x-6)(x²-x-12)
=(x-3)(x+2)(x-4)(x+3)
﹙x²-x﹚²-18﹙x²-x﹚+72
设(x²-x)=y
则原式=y²-18y+72
=(y-6)(y-12)
将(x²-x)=y带入上式,则
[(x²-x)²-6][(x²-x)²-12]
(X+3)(X-4)(X+2)(X-3)
﹙x²-x-6﹚﹙x²-x-12﹚