问学习之路团队一道数学题△ABC的顶点分别是A(2,-1)B(4,3) C(3,-2) ∠A的平分线所在的直线方程是直线AB的方程为:y=2x-5直线AC的方程为:y=-x+1设∠BAC的平分线为:y=kx+b因为经过点A所以-1=2k+b∴
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![问学习之路团队一道数学题△ABC的顶点分别是A(2,-1)B(4,3) C(3,-2) ∠A的平分线所在的直线方程是直线AB的方程为:y=2x-5直线AC的方程为:y=-x+1设∠BAC的平分线为:y=kx+b因为经过点A所以-1=2k+b∴](/uploads/image/z/3022139-11-9.jpg?t=%E9%97%AE%E5%AD%A6%E4%B9%A0%E4%B9%8B%E8%B7%AF%E5%9B%A2%E9%98%9F%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E2%96%B3ABC%E7%9A%84%E9%A1%B6%E7%82%B9%E5%88%86%E5%88%AB%E6%98%AFA%EF%BC%882%2C-1%EF%BC%89B%284%2C3%29+C%283%2C-2%29+%E2%88%A0A%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B%E6%98%AF%E7%9B%B4%E7%BA%BFAB%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9Ay%3D2x-5%E7%9B%B4%E7%BA%BFAC%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9Ay%3D-x%2B1%E8%AE%BE%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%B8%BA%EF%BC%9Ay%3Dkx%2Bb%E5%9B%A0%E4%B8%BA%E7%BB%8F%E8%BF%87%E7%82%B9A%E6%89%80%E4%BB%A5-1%3D2k%2Bb%E2%88%B4)
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