已知(a²+b²)²-(a²+b²)-6=0,求a²+b²的值
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已知(a²+b²)²-(a²+b²)-6=0,求a²+b²的值
已知(a²+b²)²-(a²+b²)-6=0,求a²+b²的值
已知(a²+b²)²-(a²+b²)-6=0,求a²+b²的值
(a²+b²)²-(a²+b²)-6=0,求a²+b²的值
把a²+b² 看做一个整体
(a²+b²-3) (a²+b² +2 ) = 0
a²+b² = 3 或者 -2 (舍去)
a²+b² =3
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已知(a²+b²)²-(a²+b²)-6=0
则,[(a^2+b^2)-3][(a^2+b^2)+2]=0
a^2+b^2-3=0 a^2+b^2+2=0
a^2+b^2=3
a^2+b^2=-2(舍去)