已知(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为多少
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已知(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为多少
已知(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为多少
已知(a²+b²)²-(a²+b²)-6=0,则a²+b²的值为多少
解;
∵(a²+b²)²-(a²+b²)-6=0
1 -3
1 2
十字交叉
∴[(a²+b²)-3][(a²+b²)+2]=0
∵a²+b²+2>0
∴a²+b²=3