3\4{4\3(1\2X-1\4)-8}=3\2X+1怎么解

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3\4{4\3(1\2X-1\4)-8}=3\2X+1怎么解
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3\4{4\3(1\2X-1\4)-8}=3\2X+1怎么解
3\4{4\3(1\2X-1\4)-8}=3\2X+1怎么解

3\4{4\3(1\2X-1\4)-8}=3\2X+1怎么解
3/4[4/3(1/2X-1/4)-8]=3/2X+1
左右两边同时乘以12
3[4(x/2-1/4)-24]=18x+12
12(x/2-1/4)-72=18x+12
6x-3-72=18x+12
移项:18x-6x=-72-3-12
12x=-87
x=-29/4

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