(x-根号下2)²+(4根号下2)x=0
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(x-根号下2)²+(4根号下2)x=0
(x-根号下2)²+(4根号下2)x=0
(x-根号下2)²+(4根号下2)x=0
(x-根号下2)²+(4根号下2)x=0
x²-2√2x+2+4√2x=0;
x²+2√2x+2=0;
(x+√2)²=0;
x=-√2;
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(x-根号下2)²+(4根号下2)x=0
无解
展开,合并同类项
x=根号2
解原方程是(x-根号下2)²+(4根号下2)x=0
得(x-√2)²+(4√2)x=0
即x²-2√x+2+4√2x=0
即x²+2√x+2=0
即(x+√2)²=0
解得x1=x2=-√2