求个最大值 (t-2/3√3)²/(3t²-1)(t-2/3根号3)²/(3t²-1)另外 类似的函数的最值怎么解?范围是 (根号3,5/3根号3)
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![求个最大值 (t-2/3√3)²/(3t²-1)(t-2/3根号3)²/(3t²-1)另外 类似的函数的最值怎么解?范围是 (根号3,5/3根号3)](/uploads/image/z/3039671-47-1.jpg?t=%E6%B1%82%E4%B8%AA%E6%9C%80%E5%A4%A7%E5%80%BC+%EF%BC%88t-2%2F3%E2%88%9A3%EF%BC%89%26%23178%3B%2F%EF%BC%883t%26%23178%3B-1%EF%BC%89%EF%BC%88t-2%2F3%E6%A0%B9%E5%8F%B73%EF%BC%89%26%23178%3B%2F%EF%BC%883t%26%23178%3B-1%EF%BC%89%E5%8F%A6%E5%A4%96+%E7%B1%BB%E4%BC%BC%E7%9A%84%E5%87%BD%E6%95%B0%E7%9A%84%E6%9C%80%E5%80%BC%E6%80%8E%E4%B9%88%E8%A7%A3%3F%E8%8C%83%E5%9B%B4%E6%98%AF+%EF%BC%88%E6%A0%B9%E5%8F%B73%EF%BC%8C5%2F3%E6%A0%B9%E5%8F%B73%EF%BC%89)
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求个最大值 (t-2/3√3)²/(3t²-1)(t-2/3根号3)²/(3t²-1)另外 类似的函数的最值怎么解?范围是 (根号3,5/3根号3)
求个最大值 (t-2/3√3)²/(3t²-1)
(t-2/3根号3)²/(3t²-1)
另外 类似的函数的最值怎么解?
范围是 (根号3,5/3根号3)
求个最大值 (t-2/3√3)²/(3t²-1)(t-2/3根号3)²/(3t²-1)另外 类似的函数的最值怎么解?范围是 (根号3,5/3根号3)
答:
设:
k=(t-2/3√3)²/(3t²-1)
=(t²-4t/3√3+4/27)/(3t²-1)
整理:
3kt²-k=t²-4t/3√3+4/27
(3k-1)t²+4t/(3√3)-k-4/27=0
方程有解,则有:
判别式=(4/3√3)²+4(3k-1)(k+4/27)>=0
所以:4/27+3k²+4k/9-k-4/27>=0
3k²-5k/9>=0
k<=0或者k>=5/27
所以:极大值为0,极小值为5/27